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Find K such that the points (-2, 5), (2, 8) and (6, K) are collinear.

User Dua Ali
by
7.2k points

1 Answer

4 votes

Answer:

k = 11

Explanation:

let the points be A(-2,5), B(2,8), C(6,K).

for the points to be collinear slope of line AB maust be equal to line BC.

slope of line AB =
(8-5)/(2+2)=(3)/(4)

slope of line BC =
(k-8)/(6-2)=(k-8)/(4)

therefore
(k-8)/(4)= (3)/(4)

therefore k = 8 + 3

k = 11

User Pilsetnieks
by
6.6k points
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