Question

15x²у⁴ (over) Зху² =

I'd like to know a break down on how to solve these types of fractions for an exam ‍♀️ Help me ...​

Answer 1

`5xy^2`

Explanation:

`(15x^2y^4)/(3xy^2) =`

Remember that numbers and variables that have no operation between them are being multiplied, so let's show the multiplications in the numerator and denominator.

`= (15 * x^2 * y^4)/(3 * x * y^2)`

Now separate the fraction into three fractions, one with numbers, one with x, and one with y.

`= (15)/(3) * (x^2)/(x) * (y^4)/(y^2)`

Divide the numbers. For the variables, use the rule that when you divide two powers with the same base, you subtract the exponents. Remember that a variable that shows no exponent has an exponent of 1. A plain x is x^1.

`= 5x^(2 - 1)y^(4 - 2)`

Now do the subtractions.

`= 5x^1y^2`

`= 5xy^2`

Once you get used to these problems, you can do all the calculations in your head and go directly from the question to the answer without having to write all these steps.

Answer 2

5XY^2

Explanation: