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Line Segment BC has endpoints B (3,5) and C (7,15). Find the missing coordinates of A (x,9) and D (17,y) such that AB and CD are perpendicular to BC.

User Trunst
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1 Answer

6 votes

Answer:

x=-7

y=11

Explanation:

Perpendicular Vectors

Two vectors defined as their endpoints
\vec u=<a,b> and
\vec v=<c,d> are perpendicular if their dot product a.b is zero. The dot product is


\vec u.\vec v=ac+bd

In other words

ac+bd=0

Let's treat all the points as the extremes of vectors, so we can easily find the missing coordinates

B (3,5) and C (7,15) define a segment, the vector


\overrightarrow{BC}=<7-3,15-5>=<4,10>

The point A is A (x,9), we need to form a vector with B


\overrightarrow{AB}=<x-3,9-5>=<x-3,4>

this vector must be perpendicular to BC, so, applying the dot product we have


4(x-3)+40=0


4x-12=-40


x=-7

The point D is D(17,y), we need to form a vector with C


\overrightarrow{CD}=<17-7,y-15>=<10,y-15>

this vector must be perpendicular to BC, so, applying the dot product we have


(4)(10)+(10)(y-15)=0


40+10y-150=0


10y=110


y=11

The points are


\boxed{A(-7,9), D(17,11)}

User Jadelord
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5.7k points