Question

The average bulk resistivity of the human body (apart from surface resistance of the skin) is about 5.0 Ωm. The conducting path between the hands can be represented approximately as a cylinder 1.6 m long and 0.10 m in diameter.

Answer 1

The question is incomplete. This is the complete version:

The average bulk resistivity of the human body (apart from surface resistance of the skin) is about 5.0Ω⋅m. The conducting path between the hands can be represented approximately as a cylinder 1.6 m long and 0.10 m in diameter. The skin resistance can be made negligible by soaking the hands in salt water. (a) What is the resistance between the hands if the skin resistance is negligible? (b) What potential difference between the hands is needed for a lethal shock current of 100 mA? (Note that your result shows that small potential differences produce dangerous currents when the skin is damp.) (c) With the current in part (b), what power is dissipated in the body?

Answer:

R = 1019 Ω

V = 102.0 V

P = 10.20 W

Step-by-step explanation:

a)
`R = (resistivity*l)/(A)\\R=(5*1.6)/(\pi*0.05^(2) ) = 1 019 ohms`

b) V = IR = 100 mA * 1019 Ω = 0.1000 A x 1 019 Ω = 102.0 V

c) P = V²/R = 102²/1019 = 10.20 W