Question

S and e are the midpoints of ba and am respectively use the properties of midsegments to find the perimeter of bam

Answer 1

Answer:50 D

Explanation:

It was right on math nation

Answer 2

50 in

Explanation:

We are given that

S and E are the midpoints of AB and AM.

We have to find the perimeter of triangle BAM by using the properties of midsegments.

EM=9 in

SE=7 in

E is the midpoint of side AM.

Therefore,EM=AE=9

AM=AE+EM=9+9=18 in

S is the mid-point of AB therefore,

AS=SB

By mid- segment theorem

SE is parallel to BM and

`SE=(1)/(2) BM`

`BM=2* SE=2* 7=14 in`

`\angle ABM+\angle AMB+\angle BAM=180^(\circ)`

Triangle angle sum property

`40+70+\angle AMB=180`

Angle AMB=
`180-70-40=70^(\circ)`

AB=AM ( Sides which make equal angles are equal)

AB=18 in

Perimeter of triangle= Sum of all threes sides

Perimeter of triangle BAM=AB+BM+AM

Substitute the values then we get

Perimeter of triangle BAM=18+14+18=50 in