Question

SO3 (g) + H2O (l) ------> H2SO4 (l)

How many moles of water will be reacted with 2.5 g of SO3 when 15 g of H2SO4 is produced?

Answer 1

Moles of
`H_2O` reacted = 0.1529 moles

Step-by-step explanation:

Mass of
`H_2SO_4` obtained = 15 g

Thus, formation of the product can be used to determine the moles of water reacted as:-

Molar mass of
`H_2SO_4` = 98.079 g/mol

The formula for the calculation of moles is shown below:

`moles = (Mass\ taken)/(Molar\ mass)`

Thus,

`Moles= (15\ g)/(98.079\ g/mol)`

`Moles_(H_2SO_4)= 0.1529\ mol`

According to the given reaction:-

`SO_3+H_2O\rightarrow H_2SO_4`

1 mole of
`H_2SO_4` forms when 1 mole of
`H_2O` is reacted

So,

0.1529 mole of
`H_2SO_4` forms when 0.1529 mole of
`H_2O` is reacted

Thus, Moles of
`H_2O` reacted = 0.1529 moles