Question

A sinusoidal electromagnetic wave is propagating in a vacuum in the +z-direction.Part AIf at a particular instant and at a certain point in space the electric field is in the +x-direction and has a magnitude of 4.90 V/m , what is the magnitude of the magnetic field of the wave at this same point in space and instant in time?Part B

What is the direction of the magnetic field?

Answer 1

Step-by-step explanation:

Given that,

Magnitude of electric field in +x direction, E = 4.9 V/m

Part A :

The relation between electric and magnetic field is given by :

`B=(E)/(c)`

c is the speed of light

`B=(4.9\ V/m)/(3* 10^8\ m/s)`

`B=1.63* 10^(-8)\ T`

So, the magnetic field of the wave at this same point in space and instant in time is
`1.63* 10^(-8)\ T`.\

Part B :

The direction of electric and magnetic field is same i.e. +x direction.

Hence, this is the required solution.