The question has no question content. But let's do the balanced reaction.
Answer:
Ca₃(PO₄)₂(aq) + 2Fe(C₂H₃O₂)₃(aq) → 3Ca(C₂H₃O₂)₂(aq) + 2FePO₄(s)
Step-by-step explanation:
The calcium phosphate is formed by the ions calcium (Ca²⁺) and phosphate (PO₄³⁻), so to do the compound we must replace the charges:
Ca₃(PO₄)₂.
The iron (III) acetate is formed by the ions iron(III) (Fe⁺³) and acetate C₂H₃O₂⁻, and its formula is Fe(C₂H₃O₂)₃.
The products of the reaction will be calcium acetate, Ca(C₂H₃O₂)₂, and iron (III) phosphate, FePO₄. Thus, the reaction is:
Ca₃(PO₄)₂(aq) + Fe(C₂H₃O₂)₃(aq) → Ca(C₂H₃O₂)₂(aq) + FePO₄(s)
To be balanced, the amount of the elements must be the same on both sides of the reaction. Som we multiply Ca(C₂H₃O₂)₂ by 3, and Fe(C₂H₃O₂)₃(aq) and FePO₄ by 2:
Ca₃(PO₄)₂(aq) + 2Fe(C₂H₃O₂)₃(aq) → 3Ca(C₂H₃O₂)₂(aq) + 2FePO₄(s)
The acetates are soluble, and calcium is not an exception, so it will be in aqueous phase; the phosphates are insoluble, calcium is an exception, but iron (III) is not, so it will precipitate.