Answer:
Therefore the required point A(x₁ , y₁) = A( -3 , 4 )
Explanation:
Given:
The midpoint of segment AB is M(1,-3)
and B(5,-10),
Let
point A( x₁ , y₁)
point B( x₂ , y₂) ≡ (5 , -10)
M(x , y) = (1 , -3 )
To Find:
point A( x₁ , y₁) = ?
Solution:
M is the midpoint of segment AB. {Given}
BY Mid point Formula we have

Substituting the given values in above equation we get

Therefore the required point A(x₁ , y₁) = A( -3 , 4 )