Answer:
![sinC=0.22](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3ml23o7ob5hyyq41nihk37o6cawhb5hxvg.png)
Explanation:
For this exercise you need to use the following Trigonometric Identity:
![sin\alpha=(opposite)/(hypotenuse)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6j5eh56eb8lcstqvo7zl1n0flvsxdmjmip.png)
In this case,given the rigth triangle ABC , you can identify that:
![\alpha=C\\opposite=AB=18\\hypotenuse=AC=82](https://img.qammunity.org/2020/formulas/mathematics/middle-school/x5wr7zadkfnbp4w58jvws5u2m222s7jas1.png)
So, knowing these values, you can substitute them into
and then evaluate.
Then, you get:
![sinC=(18)/(82)\\\\sinC=0.219](https://img.qammunity.org/2020/formulas/mathematics/middle-school/nub75noqkdk3jh8sk6remzh1spz6dx1408.png)
Finally, rounding to the nearest hundreth, you get:
![sinC=0.22](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3ml23o7ob5hyyq41nihk37o6cawhb5hxvg.png)