Question

In 2000, the circulation of a local newspaper was 3,250. In 2001, its circulation was 3,640. In 2002, the circulation was 4,100.

Find the percent of increase in the newspaper’s circulation from 2000 to 2001 and from 2001 to 2002.
Which period had a higher percent of increase, 2000 to 2001, or 2001 to 2002?


Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.

Answer 1

For the time period 2000 to 2001, the percent increase in newspaper circulation is 12 %.

For the time period 2001 to 2002, the percent increase in newspaper circulation is 12.64 %.

Explanation:

Given:

Newspapers circulation in 2000 = 3250

Newspapers circulation in 2001 = 3640

Newspapers circulation in 2002 = 4100

Now, change in newspapers circulation from 2000 to 2001 is given as:

Change for 2000-2001 = 3640 - 3250 = 390

Therefore, percent increase in newspaper circulation is given as:

`\%\ increase=\frac{\textrm{Change in circulation}}{\textrm{Original circulation in 2000}}* 100\\\%\ increase=(390)/(3250)* 100=12\%`

Therefore, for the time period 2000 to 2001, the percent increase in newspaper circulation is 12 %.

Now, change in newspapers circulation from 2001 to 2002 is given as:

Change for 2001-2002 = 4100 - 3640 = 460

Therefore, percent increase in newspaper circulation is given as:

`\%\ increase=\frac{\textrm{Change in circulation}}{\textrm{Original circulation in 2001}}* 100\\\%\ increase=(460)/(3640)* 100=12.64\%`

Therefore, for the time period 2001 to 2002, the percent increase in newspaper circulation is 12.64 %.