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What is the monomial if a square of a monomial is: 0.0001a^8x^4 and 9/25a^2n+4

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Answer:


A = 0.01a^(4)x^(2) and
A = - 0.01a^(4)x^(2)


B = (3)/(5) a^(n + 2) and
B = - (3)/(5) a^(n + 2)

Explanation:

If the square of monomials is given by the given expressions then we have to find the monomials.

Let,
A^(2) = 0.0001 a^(8)x^(4) = (0.01)^(2)(a^(4))^(2)(x^(2) )^(2) = [0.01a^(4)x^(2)]^(2)


A = 0.01a^(4)x^(2) and
A = - 0.01a^(4)x^(2)

{Square root both sides}

Again, let
B^(2) = (9)/(25)a^((2n + 4)) = (3^(2) )/(5^(2)) a^(2(n + 2)) = [(3)/(5)a^(n + 2)  ]^(2)


B = (3)/(5) a^(n + 2) and
B = - (3)/(5) a^(n + 2)

{Square root both sides} (Answer)

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