Answer:
option B
Step-by-step explanation:
given,
mass of the box = 1 Kg
spring constant = k = 1000 N/m
spring is compressed upto = 15 cm = 0.15 m
coefficient of friction = μk =0.4
using conservation of energy




v = 4.74 m/s
so, the velocity of the box = v = 4.74 m/s
hence, the correct answer is option B