Question

An 100 kg object traveling at 50 m/s collides (perfectly inelastic) with a 50 kg object initially at rest.

7. What is the sum of the momentum of both objects prior to the collision?
a. 100 kgm/s b. 500 kgm/s C. 5,000 kgm/s d. 100,000 kgm/s

Answer 1

Option C. 5,000 kg m/s

Step-by-step explanation:

Linear Momentum on a System of Particles

Is defined as the sum of the momenta of each particles in a determined moment. The individual momentum is the product of the mass of the particle by its speed

P=mv

The question refers to an 100 kg object traveling at 50 m/s who collides with another object of 50 kg object initially at rest. We compute the moments of each object

`m_1=(100\ kg)(50\ m/s)=5,000\ kg\ m/s`

`m_2=(50\ kg)(0\ m/s) = 0`

The sum of the momenta of both objects prior to the collision is

`P=5,000\ kg\ m/s+0\ kg\ m/s`

`\boxed{ P=5,000\ kg\ m/s}`