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Use this technique to find a formula for the intensity I of a sound, in terms of the sound level β and the reference intensity I0. There will be a quantity (10 dB) involved in your calculations. When you enter your answer, leave off the unit dB. Express your answer in terms of β and I0.

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The problem is basically asking us to find a way to find the sound intensity I, in terms dependent on the sound level and the reference intensity
I_0.For this purpose we can start from the unit used in the scale logarithmic decibel, that is


\beta = 10log_(10)(I)/(I_0)

Where

I = Acoustic intensity on the linear scale


I_0 = Hearing threshold

Using the logarithmic properties of the exponents the above expression can be described as:


((I)/(I_0))^(10) = 10^(\beta)


I = I_0 10^{(\beta)/(10)} \righarrow that is the expression or technique to find the intensity of sound.

User Life Of Madness
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