Answer:
The midpoint of the midsegment of the trapezoid is (p+r+s,2q).
Explanation:
The vertices of the trapezoid are O(0,0), A(4p,4q), B(4r,4q) and C(4s,0).
If a line connects the midpoints of the two nonparallel sides of the trapezoid then it is known as midsegment of a trapezoid.
OC and AB are horizontal lines because the y-coordinated of their end points are same.It means OC and AB are parallel sides. So, we can say that OA and BC are non parallel sides.
![Midpoint=((x_1+x_2)/(2),(y_1+y_2)/(2))](https://img.qammunity.org/2020/formulas/mathematics/high-school/3rol8olr1htr5mugj3196ay42gb87jux1d.png)
Midpoint of OA is
![P=((0+4p)/(2),(0+4q)/(2))=(2p,2q)](https://img.qammunity.org/2020/formulas/mathematics/high-school/w5ck8tkskqa6ttre799hnwyjuwihaw6f25.png)
Midpoint of BC is
![Q=((4r+4s)/(2),(4q+0)/(2))=(2r+2s,2q)](https://img.qammunity.org/2020/formulas/mathematics/high-school/68t36hdv1pb56t61wpv95yed722nm3ag3w.png)
Midpoint of the midsegment of the trapezoid is the midpoint of P and Q. So, the midpoint of PQ is
![M=((2p+2r+2s)/(2),(2q+2q)/(2))=(p+r+s,2q)](https://img.qammunity.org/2020/formulas/mathematics/high-school/zcdage130b1lmabhtqzntire2xaday7gw8.png)
Therefore, the midpoint of the midsegment of the trapezoid is (p+r+s,2q).