Question

A city Council consist of six democrats and eight Republicans if a committee of six people is selected find the probability of selecting 2 democrats 4 Republicans

Answer 1

The probability of selecting three Democrats and two Republicans is 0.349

Explanation:

Given:

The Number of Democrats = 6

The Number of Republicans = 8

To Find:

Probability of selecting 2 Democrats and 4 Republicans. = ?

Solution:

we have to select a committee of 6 people

Now the probability of selecting 2 Democrats and 4 Republicans.

=>
`\frac{\mathrm{P}(\text { Selecting two Democrats }) \cdot \mathrm{P}(\text { Selecting four Republicans })}{\mathrm{P}(\text { Selecting } 6 \text { member from total } 14)}`

=>
`(C(6,2) \cdot C(8,4))/(C(14,6))`

=>
`( 6 C_(2 ) \cdot 8 C_(4))/(14 C_(6))`

=>
`(15\cdot 70)/(3003)`

=>
`(1050)/(3003)`

=>0.349