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What is the equation for a line passing through (-2,3) and perpendicular to y= -1/2+1 ?

User Alex Terry
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1 Answer

3 votes

Answer:


y=2x+7

Explanation:

The correct question is

what is the equation for a line passing through (-2,3) and perpendicular to y= -1/2x+1 ?

Remember

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes are equal to -1)

The slope of the given line is m=-1/2

so

the opposite reciprocal is m=2

Find the equation of the line in point slope form


y-y1=m(x-x1)

we have


m=2\\point\ (-2,3)

substitute


y-3=2(x+2)

Convert to slope intercept form


y=mx+b

isolate the variable y


y-3=2x+4


y=2x+4+3


y=2x+7

User Xiaoguo Ge
by
8.8k points

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