Question

Write in slope-intercept form an equation of a line that passes through the given points. (1,6) and (3,2)

Answer 1

Answer: y = -2x + 8

Explanation:

To find the equation of the line , we will use the formula:

`(y_(2)- y_(1))/(x_(2)- x_(1))` =
`(y-y_(1))/(x - x_(1))`

From the question

`x_(1)` = 1

`x_(2)` = 3

`y_(1)` = 6

`y_(2)` = 2

substituting into the formula , we have

`(2 - 6)/(3 - 1)` =
`(y - 6)/(x - 1)`

`(-4)/(2)` =
`(y - 6)/(x - 1)`

cross multiplying , we have

2(y-6) = -4(x-1)

Expanding , we have

2y - 12 = -4x + 4

Adding 12 to both sides , we have

2y = -4x + 16

dividing through by 2 , we have

y = -2x + 8

Therefore , the equation of the line is given as

y = -2x + 8