Answer:
102 ft.
Explanation:
See the diagram attached.
From right triangle Δ ADC,
⇒ AC = 160 ft. {Since
}
Now, given that BC = 42 ft.
Hence, AB = AC - BC = 160 - 42 = 118 ft.
Now, from right triangle Δ AEB we can write
⇒
ft ≈ 102 ft.
Therefore, the closest distance from point A on one bank to point E on the opposite bank is 102 ft. (Answer)