Question

A spring is stretched from equilibrium to 0.90 m, and the work done on the spring equals 18 J. What is the value of the spring constant?

44 N/m

32 N/m

40 N/m

11 N/m

Answer 1

Option A

44 N/m

Step-by-step explanation:

Work,
`W=0.5kx^(2)` where k is the spring constant and x is the spring extension or compression.

Making k the subject of the formula then

`k=\frac {2W}{x^(2)}`

Substituting the figures given where 18 J is W and 0.9m is x then

`k=\frac {2* 18}{0.9^(2)}=44.444 N/m\approx 44 N/m`