162k views
0 votes
We are sending a 30 Mbit MP3 file from a source host to a destination host. All links in the path between source and destination have a transmission rate of 10 Mbps. Assume that the propagation speed is 2 * 108 meters/sec, and the distance between source and destination is 10,000 km. The END TO END DELAY(transmission delay plus propagation delay) is:__________

a. 3.05 seconds.
b. 3 seconds.
c. 6.1 seconds.

2 Answers

4 votes

Final answer:

The end-to-end delay for sending a 30 Mbit MP3 file with a transmission rate of 10 Mbps over a distance of 10,000 km, with a propagation speed of 2 * 10¸ meters/sec, is 3.05 seconds.

Step-by-step explanation:

To calculate the end-to-end delay when sending a file from a source host to a destination host, you need to consider both the transmission delay and the propagation delay. The transmission delay is the amount of time it takes to push all the file's bits onto the link. The propagation delay is the time it takes a bit to traverse the link from source to destination at the given propagation speed.

Given a file size of 30 Mbits and a transmission rate of 10 Mbps:

  • Transmission delay = file size / transmission rate = 30 Mbits / 10 Mbps = 3 seconds.



Given a propagation speed of 2 * 10¸ meters/sec and a distance of 10,000 km (which is 10,000 * 10³ meters), we get:

  • Propagation delay = distance / propagation speed = (10,000 * 10³ meters) / (2 * 10¸ meters/sec) = 0.05 seconds.


Thus, the end-to-end delay is the sum of transmission delay and propagation delay:

  • End-to-end delay = transmission delay + propagation delay = 3 seconds + 0.05 seconds = 3.05 seconds.

User Denislava Shentova
by
5.1k points
0 votes

Answer:

Option A is the correct answer.

Step-by-step explanation:

User MarioRicalde
by
5.2k points