Question

A pail of water is rotated in a vertical circle of radius r = 1.6 m . The acceleration of gravity is 9.8 m/s 2 . r v What is the minimum speed of the pail at the top of the circle if no water is to spill out? Answer in units of m/s.

Answer 1

Answer:3.95 m/s

Step-by-step explanation:

Given

radius of circle
`r=1.6 m`

Water will not spill if the centripetal acceleration is greater than acceleration due to gravity

i.e.
`a_c\geq g`

`a_c=(v^2)/(r)`

`(v^2)/(r)\geq g`

`v_(min)=√(gr)`

`v_(min)=√(9.8* 1.6)`

`v_(min)=√(15.68)`

`v_(min)=3.95 m/s`