Question

How much heat is added if 0.814g of water increase in temperature by 0.351 degree C

Answer 1

1·199 J

Step-by-step explanation:

Given

Mass of water = 0·814 g = 0·814 ×
`10^(-3)` kg

Increase in temperature = 0·351 °C

Let the amount of heat added be Q J

Formula for heat added is

Q = m × s × ΔT

where Q is the amount of heat transferred

m is the mass

s is the heat capacity

ΔT is the change in temperature

Heat capacity of water = 4200 J/kg °C

Applying the formula for heat added

Q = 0·814 ×
`10^(-3)` × 4200 × 0·351 = 1·199 J

∴ Amount of heat added = 1·199 J