Answer:the amount of money that was invested in account A is $1400
the amount of money that was invested in account B is $6000
Explanation:
Let x represent the amount of money that was invested in account A
Let y represent the amount of money that was invested in account B.
Total amount of money invested in both accounts is $20000. It means that
x + y = 20000
The formula for simple interest is expressed as
I = PRT/100
Where
P = principal or amount invested
R =interest rate
T = time
For account A
P = x
T = 1 year
R = 6%
I = x × 6 × 1)/100 = 0.06x
For account B
P = y
T = 1 year
R = 5%
I = y × 5 × 1)/100 = 0.05y
After one year , he received a total of 1140 in interest. This means that
0.06x + 0.05y = 1140 - - - - - - - -1
Substituting x = 20000 - y into equation 1, it becomes
0.06(20000 - y) + 0.05y = 1140
1200 - 0.06y + 0.05y = 1140
- 0.06y + 0.05y = 1140 - 1200
- 0.01y - 60
y = - 60/ - 0.01 = 6000
Substituting y = 6000 into
x = 20000 - y, it becomes
x = 20000 - 6000 = 14000