Question

Give the equation of the circle centered at the origin and passing through the point (0,-8)

Answer 1

The answer to your question is x ² + y² = 64

Explanation:

Process

1.- Find the length of the radius

C (0, 0)

P (0, -8)

d =
`\sqrt{(x2 - x1)^(2)+ (y2 - y1)^(2)  }`

d =
`\sqrt{(0- 0)^(2)+ (-8 - 0)^(2)  }`

d =
`√(64)`

d = 8

2.- Find the equation of the circle

`(x - h)^(2) + (y - k)^(2) = r^(2) \\`

h = 0 and k = 0

`(x - 0)^(2) + (y - 0)^(2) = 8^(2)`

x² + y² = 64