Question

Determine the gravitational force of attraction between two 3.5 kg bowling balls whose

centers are exactly 2.0 meters from each other.
F 3.06 N
G 7.00 N
H 4.09 x 10-10 N
J 2.04 x10-10 N

Answer 1

`F_G=2.04\ .\ 10^(-10)\ Nw`

Option J

Explanation:

Newton's Universal Law Of Gravitation

Newton discovered that all objects attract each other with a force of gravitational attraction which is proportional to their masses and inversely proportional to the square of the distance between them.

`\displaystyle F_G=G(m_1m_2)/(d^2)\ ,\ G=6.673\ .\ 10^(-11) N m^2/kg^2`

Where
`m_1, m_2` are the masses in kg and d is the distance between them in meters.

In the problem, we have

`m_1=m_2=3.5\ kg`

`d=2\ meters`

`\displaystyle F_G=6.673\ .\ 10^(-11) N m^2/kg^2((3.5kg)(3.5kg))/((2m)^2)`

`\boxed{F_G=2.04\ .\ 10^(-10)\ Nw}`