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Tiny water droplets in the air disperse the white light of the sun into a rainbow. What is the energy of a photon from the

red portion of the rainbow if it has a frequency of 4.57 x 10s??​

1 Answer

6 votes

Answer:

3.03 x 10⁻³² J

Step-by-step explanation:

Data Given

Frequency of the light = 4.57 x 10 s⁻¹

Energy of the photon

Solution

Formula used

E = hν

where

E = energy of photon

h = Planck's Constant

Planck's Constant = 6.626 x 10⁻³⁴ Js

ν = frequency

Put values in above equation

E = hν

E = 6.626 x 10⁻³⁴ Js x 4.57 x 10 s⁻¹

E = 3.03 x 10⁻³² J

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