Question

I need help with this ... I don't understand it ..can anyone please help me with it .. It is due today

Answer 1

1) x=0,2

2) x=2,-1

3) x =-2,1

4)x= -1

Explanation:

Normal procedure for all polynomial :

1. Differentiate Function given with respect to x.
2. Equate with zero
3. Find the roots and these are answers.

1)
`(df)/(dx)=-3x^(2) +6x`

roots of this quadratic are =0 ,2

2)
`(df)/(dx)=3x^(2) +3x-6`

roots of this quadratic =2, -1

3)
`(df)/(dx)=3x^(3)+3x^(2) -6x`

Roots of this cubic =-2,1