Question

A box contains four red balls and eight black balls. Two balls are randomly chosen from the box, and are not

replaced. Let event B be choosing a black ball first and event R be choosing a red ball second.
What are the following probabilities?
P(B) =
P(RIB) =
P(BNR)=
The probability that the first ball chosen is black and the second ball chosen is red is about percent.​

Answer 1

(1) 8/12 (2) 4/11 (3) 8/33 (4) 24%

Answer 2

the probabilities will be following

P(B) = 8/12

P(RIB) = 4/11

P(BNR)= 8/33

probability that the first ball chosen is black and the second ball chosen is red is about = 24 %