Answer:
the cost of one hot chocolate is $2.
Explanation:
Let x be the hot chocolate cost and y be the newspaper cost.
Given:
A newspaper and three hot chocolates cost $7
So, the equation is
--------(1)
Two newspapers and two hot chocolates cost $6
So, the second equation is.
---------(2)
Find one hot chocolate cost?
Solve equation 1 for y.
![3x+y=7](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7c5rcvceoln1rzqvgk2zf0hfs1kqducai3.png)
![y=7-3x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wgtjhc7cbx4r3r66kx1y929m1bf941rrhu.png)
Put y value in equation 2
![2x+2(7-3x)=6](https://img.qammunity.org/2020/formulas/mathematics/middle-school/g29wmmt6ppyr84aw39tbvyt1m2hee16w5t.png)
![2x+14-6x=6](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4704jsddpjlbm5gqzg2bo2qzljjj9tmlih.png)
![14-4x=6](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lnsibbsusy6m6mqhowultu8kvkxykld2kf.png)
![-4x=6-14](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4o14rscx8jtoid09rm7f4466ar8j0xlth8.png)
![-4x=-8](https://img.qammunity.org/2020/formulas/mathematics/middle-school/289wpuy7t5fum60lai92335vjp08jj4pb9.png)
negative sign is cancelled both side.
![x=(8)/(4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/it3gcnz14ka8uf42xst59knvrd2zizrtp1.png)
![x=2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rgwu4x0cp6hdykhfamznd7kqdkp0xgsg9s.png)
Therefore, the cost of one hot chocolate is $2.