Question

A cylindrical blood vessel is partially blocked by the buildup of plaque. At one point, the plaque decreases the diameter of the vessel by 69.0 %. The blood approaching the blocked portion has speed v 0 . Just as the blood enters the blocked portion of the vessel, what is its speed v , expressed as a multiple of v 0

Answer 1

Answer:10.4 times of initial velocity

Step-by-step explanation:

Given

Diameter reduced by 69 %

it approaches with velocity
`v_0`

suppose its velocity is v during blocked passage

suppose d is the initial diameter and
`d_2` diameter is

`d_2=d(1-0.69)`

`d_2=0.31 d`

`A_2=(\pi d_2^2)/(4)`

As flow is constant

`Q_1=Q_2`

`d^2v_0=d_2^2v`

`v=10.40 v_0`