209k views
1 vote
Write the point-slope form of the equation of the line using the point (-4,-2)

User RibeiroSt
by
4.0k points

2 Answers

9 votes

Answer:

sheesh

Explanation:

User Koerr
by
4.2k points
5 votes

Note: Maybe you either forgot to mention the slope or forgot to mention another point from which the equation of the line passes.

In the later part, I would assume the slope m = 2 as an example.

Answer:

Please check the explanation.

Explanation:

Given

  • The point (-4, -2)

The point-slope form:

The point-slope form of the line equation is defined as


y-y_1=m\left(x-x_1\right)

where

  • m is the slope of the line
  • (x₁, y₁) is the point

In our case:

(x₁, y₁) = (-4, -2)

substituting the point (-4, -2) in the point-slope form of the equation of the line


y-y_1=m\left(x-x_1\right)


y-\left(-2\right)=m\left(x-\left(-4\right)\right)

Therefore, the point-slope form of the equation of the line using the point (-4,-2) will be:


  • y-\left(-2\right)=m\left(x-\left(-4\right)\right)

BONUS!

Example Solving with assuming the slope m = 2

Let suppose the slope m = 2

As we have already got the equation in the point-slope form


y-\left(-2\right)=m\left(x-\left(-4\right)\right)

substituting m = 2


y-\left(-2\right)=2\left(x-\left(-4\right)\right)


y+2=2\left(x+4\right)

Subtract 2 from both sides


y+2-2=2\left(x+4\right)-2


y=2x+6

Thus, the point-slope form of the equation of the line using the point (-4,-2) and having slope m = 2.

User Saraedum
by
3.9k points