Question

Solve for x in the equation 2 x squared minus 5 x + 1 = 3.

Answer 1

It's D.

Explanation:

Answer 2

`x=\frac{5(+/-)√(41)} {4}`

Explanation:

The formula to solve a quadratic equation of the form

`ax^(2) +bx+c=0`

is equal to

`x=\frac{-b(+/-)\sqrt{b^(2)-4ac}} {2a}`

in this problem we have

`2x^(2) -5x+1=3`

equate to zero

`2x^(2) -5x+1-3=0`

`2x^(2) -5x-2=0`

so

`a=2\\b=-5\\c=-2`

substitute in the formula

`x=\frac{-(-5)(+/-)\sqrt{-5^(2)-4(2)(-2)}} {2(2)}`

`x=\frac{5(+/-)√(41)} {4}`