96.3k views
5 votes
A 44-turn rectangular coil with length ℓ = 17.0 cm and width w = 8.10 cm is in a region with its axis initially aligned to a horizontally directed uniform magnetic field of 765 mT and set to rotate about a vertical axis with an angular speed of 64.0 rad/s.

(a) What is the maximum induced emf in the rotating coil?

(b) What is the induced emf in the rotating coil at t = 1.00 s?

(c) What is the maximum rate of change of the magnetic flux through the rotating coil?

1 Answer

5 votes

Answer:

The maximum induced emf in the rotating coil = 29.66V

The induced emf in the rotating coil when (t = 1.00 s) = 26.66V

The maximum rate of change of the magnetic flux through the rotating coil = 0.674Wb/s

Step-by-step explanation:

Lets state the parameters we are being given right from the question:

Number of rectangular coil, (N) = 44

Length of Coil, l =17cm in meters we have; (l) = 17 × 10⁻² m

Width of Coil, w =8.10cm in meters we have; (w) = 8.10 × 10⁻² m

Magnitude of Uniform Magnetic Field (B) = 767mT= 765 × 10⁻³ T

Angular Speed of Coil, (ω) = 64 rad/s

(a)

To calculate the induced emf in the rotating cell,we can use the formula:

emf = NBAωsin(ωt)

For maximum induced emf, the value of sin(ωt) will be 1


emf_max = NBAω ; if (A = l × w) , we have:


emf_max = NB(l × w)ω

subsitituting the parameters into the above equation; we have:


emf_max = 44 × 765 × 10⁻³ ( 17 × 10⁻² × 8.10 × 10⁻² ) × 64

= 29.66V

(b)

At t = 1s, the induced emf is calculated as:

emf = NBAωsin(ωt)

substituting the parameters into the equation, we have:

emf = 44 × 765 × 10⁻³ ( 17 × 10⁻² × 8.10 × 10⁻² ) × 64 × sin (64 × 1)

=26.66V

(c)

To calculate the maximum rate of change of the magnetic flux through the rotating coil; we need to reflect on the equation for the maximum induced emf in terms of magnetic flux.

i.e
emf_max =
N(d∅)/(dt)

since
emf_max = 29.66 and N = 44; we have:

29.66 =
44(d∅)/(dt)


(d∅)/(dt) =
(29.66)/(44)

= 0.674 Wb/s

User Joao Almeida
by
5.2k points