122k views
1 vote
What is the equation of the line that is parallel to the line y = - 1/3x + 4 and passes through the point (6, 5)?

What is the equation of the line that is parallel to the line y = - 1/3x + 4 and passes-example-1
User Wally Ali
by
8.0k points

1 Answer

4 votes

Answer:


y=-(1)/(3)x+7

Explanation:

we know that

If two lines are parallel then their slopes are equal

The equation of the given line is


y=-(1)/(3)x+4

the slope is
m=-(1)/(3)

so

the slope of the parallel line to the given line is also
m=-(1)/(3)

Find the equation of the line that is parallel to the given line and passes through the point (6, 5)

we have


m=-(1)/(3)


point\ (6,5)

The equation of the line in point slope form is


y-y1=m(x-x1)

substitute


y-5=-(1)/(3)(x-6)

Convert to slope intercept form


y=mx+b

isolate the variable y


y-5=-(1)/(3)x+2


y=-(1)/(3)x+2+5


y=-(1)/(3)x+7

User Wordpressor
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories