Question

A certain man has a mass of 83.0 kg and a density of 996 kg/m3 (excluding the air in his lungs). (a) Calculate his volume (in m3). m3 (b) Find the buoyant force (in N) air exerts on him. N (c) What is the ratio of the buoyant force to his weight

Answer 1

Step-by-step explanation:

Given

Mass of man
`m=83 kg`

density
`\rho =996 kg/m^3`

volume
`V=(m)/(\rho )`

`V=(83)/(996)=0.0833 m^3`

(b)Buoyant Force by Air

`\rho _(air)=1.29 kg/m^3`

`F_b=\rho _(air)Vg`

`F_b=1.29* 0.0833* 9.8`

`F_b=1.053 N`

(c)Ratio of the buoyant Force to his weight

`=(F_b)/(Weight)`

Weight=mg

`weight=83* 9.8=813.4 N`

`Ratio=(1.053)/(813.4)=0.00129`