Question

The triceps muscle in the back of the upper arm extends the forearm. This muscle in a professional boxer exerts a force of 1783 N with an effective perpendicular lever arm of 2.80 cm , producing an angular acceleration of the forearm of 120.0 rad / s 2 . What is the moment of inertia of the boxer's forearm

Answer 1

Answer:I=0.416kgm^2

Step-by-step explanation:

Torque is the rotational equivalence of Force and mathematicallly, it is given by

T = r X F

Where

T=Torque

r= perpendicular distance between the applied force and the axis

F =force

T= 0.028 X 1783 =49.924 Nm

T=αI

Where α=angular acceleration produ ed

I=moment of inertia

I= T/α

I= 49.924/120

I= 0.416kgm^2