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A heat engine operates between a hot reservoir with a temperature of 400 K and a cold reservoir with a temperature of 300 K. The engine accepts 500 J of energy from the hot reservoir, does 150 J of work, and exhausts 350 J of energy into the cold reservoir. 1) Does this engine violate any laws of thermodynamics?

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Answer:

Step-by-step explanation:

Given

Temperature of Hot reservoir
T_1=400 K

Temperature of Cold reservoir
T_2=300 K

Heat reservoir
Q=500 J

Work done
W=150 J

heat Exhaust
Q_(rejection )=350 J


Q=W+Q_(rejected)


500=150+350

L.H.S=R.H.S

thus it follows first law


\eta _(carnot)=1-(T_L)/(T_H)


\eta _(carnot)=1-(300)/(400)


\eta _(carnot)=0.25

Cycle Efficiency


\eta =(W)/(Q)=(150)/(500)=0.3

Carnot efficiency is less than cycle thus it violates second law

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