Weight of one tin of bean is 0.41 kg
Solution:
Given that total weight of five tins of beans and one tin of coffee is 2.8 kg
The weight of the tin of coffee is 750 g
we know that,
![1 gram = (1)/(1000) kilograms](https://img.qammunity.org/2020/formulas/mathematics/college/ozerc1qz1i8sx499jh7f32k9qfmh5osqah.png)
![750 gram = (750)/(1000) = 0.75 kg](https://img.qammunity.org/2020/formulas/mathematics/college/11r0u2jnqpjljnfk0tp93r5b473beczwap.png)
weight of one tin of coffee = 0.75 kg
To find: weight of each tin of bean, which means we have to find weight of one tin of bean
From given information,
weight of five tins of beans + one tin of coffee = 2.8 kg
weight of five tins of beans + 0.75 kg = 2.8 kg
weight of five tins of beans = 2.8 kg - 0.75 kg = 2.05 kg
![\text {weight of one tin of bean }=\frac{\text { weight of five tins of bean }}{5}](https://img.qammunity.org/2020/formulas/mathematics/college/vaokdo04nbsavgltgq18zhvnm3jxj9m6a2.png)
![\text { weight of one tin of bean }=(2.05)/(5)=0.41](https://img.qammunity.org/2020/formulas/mathematics/college/aon1fu7bo66dsd93gtnce7qbl98gaeq704.png)
Thus weight of one tin of bean is 0.41 kg