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A metal wire is in thermal contact with two heat reservoirs at both of its ends. Reservoir 1 is at a temperature of 781 K, and reservoir 2 is at a temperature of 335 K. Compute the total change in entropy arising from the conduction of 1477 J of heat through the wire. Please give your answer in units of J/K.

User TARehman
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1 Answer

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Answer:2.517 J/K

Step-by-step explanation:

Given

Reservoir 1 Temperature
T_1=781 K

Reservoir 2 Temperature
T_2=335 K

Let Q is the amount of heat Flows i.e.
Q=1477 J

thus change in Entropy is given by
(\sum Q)/(T)


\Delta S=(\sum Q)/(T)=-(Q)/(T_1)+(Q)/(T_2)


\Delta S=(\sum Q)/(T)=-(1477)/(781)+(1477)/(335)


\Delta S=(\sum Q)/(T)=-1.891+4.4089


\Delta S=(\sum Q)/(T)=2.517 J/K

User Guilherme Meireles
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