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Someone just robbed a bank. The police set a triangular perimeter of 16 kilometers where the robber may be hiding. Two of the three

coordinates for this triangular perimeter are (2, 2) and (2, -1). Each unit represents a kilometer. The area covered is a 12 square kilometers
Which of the following is the third coordinate of the triangular perimeter?

2 Answers

2 votes

Final answer:

To find the third coordinate of the triangular perimeter, we can use the concept of area of a triangle. By using the given coordinates, the distance formula, and the equation of the line passing through the two given points, we can solve a system of equations to find the values of x and y.

Step-by-step explanation:

The third coordinate of the triangular perimeter can be found by using the concept of area of a triangle. We know that the area of the triangle is 12 square kilometers and the base of the triangle is the distance between the two given coordinates, which is 3 kilometers. Let's assume the third coordinate is (x, y). We can use the formula for the area of a triangle:

Area = (base * height) / 2

Substituting the known values, we get:

12 = (3 * height) / 2

Solving for height, we find:

height = 8 kilometers

Now, we can use the given coordinates to find the distance between them, which is the height of the triangle. Using the distance formula, we have:

height = sqrt((x-2)^2 + (y+1)^2)

Squaring both sides and rearranging the equation, we get:

(x-2)^2 + (y+1)^2 = 64

Since we have two unknowns, we need another equation to solve for x and y. Let's use the equation of the line passing through the two given points:

y - 2 = (2 - (-1)) / (2 - 2) * (x - 2)

Expanding and rearranging the equation, we get:

3x - y - 6 = 0

Now, we have a system of equations:

(x-2)^2 + (y+1)^2 = 64

3x - y - 6 = 0

Solving this system of equations will give us the values of x and y, which represent the third coordinate of the triangular perimeter.

User KristofferR
by
6.0k points
3 votes

Answer:

Step-by-step explanation:

Perimeter = 16 km

s = 8 km

Area =
√(s(s-a)(s-b)(s-c))

Area = 12 sq km

Let the third coordinate be (x,y).

Then, a =
\sqrt{(2-2)^(2)+(2-(-1))^(2)  }

=3

b =
\sqrt{(x-2)^(2)+(y-2)^(2)  }

c =
\sqrt{(x-2)^(2)+(y-(-1))^(2)  }

Solving, a+b+c = 16

and using area equation we get

x = -6

y = 2

User BearsEars
by
6.5k points