Answer
given,
speed of car = 60 km/hr
= 60 x 0.278 m/s
= 16.68 m/s
radius of the tire = 25 cm = 0.25 m
time taken to stop = 6 s
average acceleration = ?


average acceleration=

=

= 11.12 rad/s²
correct answer option D
b) length of sea saw = 10 m
mass of jack = 100 Kg
mass of Jill = 60 Kg
Let y be the distance from the Jack. To balance the seesaw moment on both side should balance each other about fulcrum
now,
100 x y = 5 x 60
y = 3 m
the correct answer is option B