Answer:
Smallest collector size≈30

Step-by-step explanation:
Daily sunlight intensity = 1400
.
For a collector of 24% efficiency, the absorption per day per

= 0.24*1400 = 336
.
For 8 hours, 25days of available sunlight, energy absorbed by collector per metre square , will be = 8* 25 *336 = 67200wh.
This is the amount of sunlight energy which will be trapped by 1
. of collector in a month.
To find how many metre square of collector is required to get 2*
kwh, we simply divide the required energy by the amount absorbed per square metre.
Smallest size of collected needed =

=29.76
≈30
