Question

Amines can be made by the reduction of nitriles, which in turn can be made from an alkyl halide. Draw the structures of a starting alkyl bromide and the intermediate nitrile that would be used in the synthesis of 3-methylbutylamine (also known as isoamylamine). Do not show free ions.

Answer 1

The structrues are shown below.

Step-by-step explanation:

The compound 3-methylbutylamine has 4 carbons at the principal chain with simple bonds between then (butyl), has a ramification with a CH₃ group at the carbon 3 (methyl), and at the carbon 1 has the amine group NH₂, as shown below.

A nitrile is a compound that has the bond C≡N at the structure, so the nitrile that originates the amide must be the 3-methylbutylnitrile, with the structure shown below (only eliminated the hydrogens from N and carbon, and then added the triple bond).

The alkyl bromide must react with a cyanide salt, which will replace the Br for CN in the compound, so we must replaced the CN for Br in the structure shown below, having the Bromo-2-methylpropane.