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Water is circulating through a closed system of pipes in a two floor apartment. On the first floor, the water has a gauge pressure of 3.70 105 Pa and a speed of 2.3 m/s. However, on the second floor, which is 3.6 m higher, the speed of the water is 3.6 m/s. The speeds are different because the pipe diameters are different. What is the gauge pressure of the water on the second floor?

User Martin B
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1 Answer

6 votes

Answer:
P_2=3.30* 10^5 Pa

Step-by-step explanation:

Given

For First Floor


P_1=3.7* 10^5 Pa


v_1=2.3 m/s


z_1=0 m

For second Floor


z_2=3.6 m


v_2=3.6 m/s

Applying Bernoulli's equation


P_1+(1)/(2)\rho v_1^2+\rho gz_1=P_2+(1)/(2)\rho v_2^2+\rho gz_2


P_2=P_1+(1)/(2)(\rho v_1^2-\rho v_2^2)+\rho g(z_1-z_2)


P_2=3.30* 10^5 Pa

User Leppert
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