Question

Water is circulating through a closed system of pipes in a two floor apartment. On the first floor, the water has a gauge pressure of 3.70 105 Pa and a speed of 2.3 m/s. However, on the second floor, which is 3.6 m higher, the speed of the water is 3.6 m/s. The speeds are different because the pipe diameters are different. What is the gauge pressure of the water on the second floor?

Answer 1

Answer:
`P_2=3.30* 10^5 Pa`

Step-by-step explanation:

Given

For First Floor

`P_1=3.7* 10^5 Pa`

`v_1=2.3 m/s`

`z_1=0 m`

For second Floor

`z_2=3.6 m`

`v_2=3.6 m/s`

Applying Bernoulli's equation

`P_1+(1)/(2)\rho v_1^2+\rho gz_1=P_2+(1)/(2)\rho v_2^2+\rho gz_2`

`P_2=P_1+(1)/(2)(\rho v_1^2-\rho v_2^2)+\rho g(z_1-z_2)`

`P_2=3.30* 10^5 Pa`