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How to write (7,-6);m= 1/2 in slope intercept form?

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\bf (\stackrel{x_1}{7}~,~\stackrel{y_1}{-6})~\hspace{10em} \stackrel{slope}{m}\implies \cfrac{1}{2} \\\\\\ \begin{array}c \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-6)}=\stackrel{m}{\cfrac{1}{2}}(x-\stackrel{x_1}{7})\implies y + 6 = \cfrac{1}{2}x-\cfrac{7}{2} \\\\\\ y = \cfrac{1}{2}x-\cfrac{7}{2}-6\implies y = \cfrac{1}{2}x-\cfrac{19}{2}

User Jan Kukacka
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2 votes

Since the question already give the slope we only need to find the y-intercept.

Slope-intercept form: y = mx + b

-6 = 1/2(7) + b

-6 = 3.5 + b

-6 - 3.5 = 3.5 - 3.5 + b

-9.5 = b

Now, we can write this in slope-intercept form.

y = 1/2x - 9.5

Best of Luck!

User Plaute
by
7.6k points

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