Question

Assume that a force acting on an abject is given by F⃗ = a x ihat + b y jhat, where the constants a = 3.0N/m and b = 4.0N/m. Determine the work done on the object by this force as it moves in a straight line from the origin to r⃗ = (10 ihat + 20 jhat) m.

Answer 1

W = 950J

Step-by-step explanation:

From the problem we have these values:

F = [3x,4y]N

ΔX = 10m

ΔY = 20m

`W = \int\limits {F} \, dr`

`W = \int\limits^(10)_0 {3x} \, dx +\int\limits^(20)_0 {4y} \, dy`

`W = 150 J+800 J`

`W = 950 J`