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Joyce has a cone shaped planter hanging on her back porch. If the planter has a radius 6.8 inches and a height of 12.2 inches, what is the total amount of soil that the planter will hold to the nearest tenth

1 Answer

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Answer:

The total amount of soils that planter will hold to it is 590.45 inches³

Explanation:

Given as :

The radius of the cone shape planter = r = 6.8 inches

The height of the cone shape planter = h = 12.2 inches

Let The total amount of soils that will hold to it = x cubic inches

Now, According to question

The total amount of soils that planter will hold to it = The volume of the cone

The volume of cone = v =
(1)/(3) \pi r² h

where r is the radius

And h is the height

So, The total amount of soils that planter will hold to it =
(1)/(3) \pi r² h

or, x =
(1)/(3) ×
\pi × r² × h

or, x =
(1)/(3) × 3.14 × (6.8)² inches × 12.2 inches

or, x =
(1)/(3) × 3.14 × 564.128 inches³

or, x =
(1)/(3) × 1771.361 inches³

or, x =
(1771.361)/(3) inches³

∴ x = 590.45 inches³

So, The total amount of soils that planter will hold to it = x = 590.45 inches³

Hence, The total amount of soils that planter will hold to it is 590.45 inches³ . Answer

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