Question

A container is filled to a depth of 0.9490.949m with water. On top of the water floats a 1.971.97m-thick layer of oil with density 700700kg/m^3 ​3 ​​ . What is the absolute pressure at the bottom of the container if the whole thing is placed in ordinary atmosphere at sea level? Give your answer in units of atm.

Answer 1

Answer:124.14 KPa

Step-by-step explanation:

Given

Layer of water is 0.949 m thick

Layer of oil is 1.971 m thick with density

`\rho _(o)=700 kg/m^3`

density of water
`\rho _(w)=1000 kg/m^3`

suppose Atmospheric Pressure be 101.325 KPa

Absolute Pressure at bottom is =Pressure at top +Pressure due to Oil and water

`P_(abs)=101.325* 10^3+\rho _(o)\cdot g\cdot 1.971+\rho _(w)\cdot g\cdot 0.949`

`P_(abs)=101.325* 10^3+700* 9.8* 1.971+1000* 9.8* 0.949`

`P_(abs)=101.325+13.521+9.3002\ KPa`

`P_(abs)=124.14 KPa`